Question #237515

A ski jumper speed down a slope and exits the ski track in a horizontal direction with a velocity of 25 m/s where the landing inclines falls off with a slope of 33 degrees.

1. What is the halftime of flight of the ski jump?

2. What is the range of the ski jumper when it lands?



1
Expert's answer
2021-09-15T11:38:03-0400

Given:

v0=25m/sv_0=25\:\rm m/s

θ=33\theta=33^{\circ}


1. the halftime of flight

t=v0sinθg=25sin339.8=1.4st=\frac{v_0\sin\theta}{g}=\frac{25\sin33^{\circ}}{9.8}=1.4\:\rm s

2. the range

R=v02sin2θg=252sin669.8=58mR=\frac{v_0^2\sin2\theta}{g}=\frac{25^2\sin66^{\circ}}{9.8}=58\:\rm m


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