a bowling ball of mass 7kg is thrown with a speed of 11m/s at a single bowling pin of mass 1.5kg. Calculate the speed the pin moves at after the collision, if the ball continued at a speed of 6m/s
"MV=MV'+mv'\\to v'=(MV-MV')\/m="
"=(7\\cdot 11-7\\cdot6)\/1.5=23.3\\ (m\/s)" . Answer
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