Question

a bowling ball of mass 7kg is thrown with a speed of 11m/s at a single bowling pin of mass 1.5kg. Calculate the speed the pin moves at after the collision, if the ball continued at a speed of 6m/s

Answer 1

$MV=MV'+mv'\to v'=(MV-MV')/m=$

$=(7\cdot 11-7\cdot6)/1.5=23.3\ (m/s)$ . Answer