Question

A boy on a bridge throws a stone horizontally with a speed of 25 m/s, releasing the stone from a point 19.6 m above the surface of the river. How far from a point directly below the boy will the stone strike the water?

Answer 1

Given:

$v_0=25\:\rm m/s$

$H=19.6\:\rm m$

The horizontal distance

$$L=v_0\sqrt{\frac{2H}{g}}=25\sqrt{\frac{2*19.6}{9.8}}=50\:\rm m$$