Question #236316

A turtle crawls along a straight line, which we will call the 𝑥-axis with a positive direction to the right. The equation for the turtle’s position as a function of time is 𝑥(𝑡) = 50.0𝑐𝑚 + (12.00𝑐𝑚/𝑠 2 )𝑡. (a) Find the turtle’s initial velocity, initial position, and initial acceleration. (b) At what time 𝑡 is the velocity of the turtle zero?


1
Expert's answer
2021-09-12T18:59:51-0400

The equation of motion of the turtle is given by

𝑥(𝑡)=50.0cm+(12.00cm/s2)𝑡2.𝑥(𝑡) = 50.0\:{\rm cm} + (12.00{\:\rm cm/s^2} )𝑡^2.

(a) the turtle’s initial position

x0=x(0)=50.0cmx_0=x(0)=50.0\:\rm cm

the turtle’s velocity

v(t)=x(t)=24.0cm/s2tv(t)=x'(t)=24.0{\:\rm cm/s^2}t

the turtle’s initial velocity

v0=v(0)=0v_0=v(0)=0

the turtle’s initial acceleration

a(0)=v(0)=24.0cm/s2a(0)=v'(0)=24.0\:\rm cm/s^2

(b) the velocity of the turtle is zero at the instant

t=0t=0


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