Given:
θ=60∘
v0=6m/s
x=2m
(a) the equation of trajectory of a ball is given by
y=xtanθ−2v02cos2θgx2So
y=2tan60∘−2∗62∗cos260∘9.8∗22=1.3m(b)
x=v0cosθ∗t
t=v0cosθx=6∗cos60∘2=0.67sThe components of velocity vector are
vx=v0cosθ=6∗cos60∘=3m/s
vy=v0sinθ−gt=6∗sin60∘−9.8∗0.67=−1.3m/sThe velocity is directed downward.
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