Question #233890

A force of 100 N directed 30 degrees from negative y-axis in quadrant three can be presented by


Expert's answer

A force of 100 N directed 30 degrees from negative y-axis in quadrant three can be presented by xx and yy components:


Fx=100 N⋅cos(270∘−30∘)=−50 N,F_x=100\ N\cdot cos(270^{\circ}-30^{\circ})=-50\ N,Fy=100 N⋅sin(270∘−30∘)=−86.6 N.F_y=100\ N\cdot sin(270^{\circ}-30^{\circ})=-86.6\ N.
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