Question

A force of 100 N directed 45 degrees from negative x-axis in quadrant two can be presented by.

 

Answer 1

A force of 100 N directed 45 degrees from negative x-axis in quadrant two can be presented by $x$ and $y$ components:

$$F_x=100\ N\cdot cos(180^{\circ}-45^{\circ})=-70.7\ N,$$ $$F_y=100\ N\cdot sin(180^{\circ}-45^{\circ})=70.7\ N.$$