A boy tosses a coin upward with a velocity of 14.7 m/s then catches it on his hand. Find the maximum height reached by the coin.
h=v22g=14.722⋅9.8=11.025 (m).h=\frac{v^2}{2g}=\frac{14.7^2}{2\cdot9.8}=11.025\ (m).h=2gv2=2⋅9.814.72=11.025 (m). Answer
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