Question #233830

A car starting from rest accelerates for 15 min. until its velocity is 20 m/s. It then moves at a constant velocity from another 20 min. before it slows down and finally stopped in another 10 m. Find the acceleration during the first 15 min.


1
Expert's answer
2021-09-09T10:49:28-0400

Given:

v0=0,v_0=0,

t1=15min=900st_1=15\:\rm min=900\: s

v1=20m/sv_1=20\:\rm m/s


The acceleration during the first 15 min

a=ΔvΔt=v1v0t1a=\frac{\Delta v}{\Delta t}=\frac{v_1-v_0}{t_1}

a=20m/s0m/s900s=0.022m/s2a=\frac{20\:\rm m/s-0\: m/s}{900\:\rm s}=0.022\:\rm m/s^2


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