A student is running at a constant velocity of 5 m/s in an effort to catch a bus parked at a station. When he is 10 m away from the bus, the bus pulls away with constant acceleration of 1.2 m/s2. How much time will it take the student to catch the bus if he keeps running with the same velocity?
Given:
"v=5\\:\\rm m\/s"
"a=1.2\\:\\rm m\/s^2"
"l=10\\:\\rm m"
The distance traveled by a student
"d_s=vt"The distance traveled by a bus
"d_b=at^2\/2"We get
"d_s+l=d_b""vt+l=at^2\/2"
"5t+10=0.6t^2"
"0.6t^2-5t-10=0"
Root
"t=3.3\\:\\rm s"
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