Answer to Question #233783 in Physics for Ban

Question #233783

A man moves a mass of 95kg with a velocity of 15.3m/s. After sometime, he suddenly bumped into a big box and released the energy of 2013 J as work. What is now the new velocity of the mass after the event


1
Expert's answer
2021-09-06T11:33:12-0400

The energy-work theorem gives

"\\frac{mv_2^2}{2}-\\frac{mv_1^2}{2}=W"

Hence, the new velocity of the mass after the event

"v_2=\\sqrt{v_1^2+2W\/m}\\\\=\\sqrt{(15.3\\:\\rm m\/s)^2+2*(-2013\\:\\rm J)\/95\\:\\rm kg}\\\\=13.8\\:\\rm m\/s"


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