Question #233756

A ball is kicked at an angle of 35 with the ground . What is the initial velocity of the ball so that it hits a target that is 30 metres away at a height of 1.8 metres?


Expert's answer

Given:

θ=35∘\theta=35^{\circ}

x=30 mx=30\:\rm m

y=1.8 my=1.8\:\rm m


The trajectory equation of a ball

y=xtan⁡θ−gx22v02cos⁡2θy=x\tan\theta-\frac{gx^2}{2v_0^2\cos^2\theta}

We get

1.8=21−6572/v021.8=21-6572/v_0^2

Finally,

v0=342=19 m/sv_0=\sqrt{342}=19\:\rm m/s


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