Question #233593

Two forces of 10 N each are acting on a point. One force acts east and the other 70 o north of east. Find the resultant displacement using the laws of sine and cosine.



Expert's answer

The angle between these two forces is θ=70°\theta = 70\degree. Accoring to the cosine law, the diagonal of the parallelogram formed by these two forces (the resultant force) is:


F=102+102+2⋅10⋅10⋅cos⁡70°≈16NF = \sqrt{10^2 + 10^2 + 2\cdot 10\cdot 10\cdot \cos70\degree} \approx 16N

Answer. 16 N.


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