A woman driving a car 14 ft long is passing a truck 30 ft long. The truck is
traveling at 50 mi/h.
How fast must the woman drive her car so that she can pass the truck
completely in 6 seconds,
30 ft=9.144 m30\ ft=9.144\ m30 ft=9.144 m
14 ft=4.2672 m14\ ft=4.2672\ m14 ft=4.2672 m
50 mi/h=22.352 m/s50\ mi/h=22.352\ m/s50 mi/h=22.352 m/s
(v2−v1)t=s1+s2→(v2−22.352)⋅6=9.144+4.2672→(v_2-v_1)t=s_1+s_2\to(v_2-22.352)\cdot6=9.144+4.2672\to(v2−v1)t=s1+s2→(v2−22.352)⋅6=9.144+4.2672→
v2=24.5872 (m/s)=55 (mi/h)v_2=24.5872\ (m/s)=55\ (mi/h)v2=24.5872 (m/s)=55 (mi/h) . Answer
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments