Answer to Question #233024 in Physics for lll

Question

a ball is kicked with an initial velocity of 11.1 m/s in the horizontal direction and 13.5 m/s in the vertical direction. At what speed does the ball hit the ground? Assume a level ground. What maximum height is attained by the ball?

Answer 1

Given:

$v_x=11.1\:\rm m/s$

$v_y=13.5\:\rm m/s$

At the ground level the final speed is equal to initial speed

$$v_f=v_i=\sqrt{v_x^2+v_y^2}=\sqrt{11.1^2+13.5^2}=17.5\:\rm m/s$$

The maximum height is attained by the ball is given by

$$h_{\max}=\frac{v_y^2}{2g}=\frac{13.5^2}{2*9.8}=9.30\:\rm m$$