Question

Calculate the acceleration of the electron which electronic charge is given as(1.60×10^-19c) and mass of electron as (9.1×10^-3kg)

Answer 1

Suppose the electric field in the place of electron's location be $E$. Then the force on election is:

$$F =eE$$

where $e = 1.6\times 10^{-19}C$ is the charge of electron. According to the second Newton's law, the acceleration of the electron is:

$$a = \dfrac{F}{m} = \dfrac{eE}{m}$$

where $m = 9.1\times 10^{-31}kg$ is the mass of electron. Substituting the particelar value of $E$ one can find the particular value of acceleration.

Answer. $a = \dfrac{eE}{m}$.