Question #231908
A meter rule is hung by two light strip tied at the 15cm, and 75 cm mark respectively to a
ceiling. If the weight of the ruler is 2N. (i) calculate the tension in the two string.
1
Expert's answer
2021-09-02T10:42:20-0400

Draw the diagram:



According to equilibrium of forces:


TA+TBW=0, TA+TB=W=2N.T_A+T_B-W=0,\\\space\\ T_A+T_B=W=2\text N.

The total tension in the two strings is 2N.


Find the torque around point A:


1522(15/100)8522(85/100)+60TB=0, TB=1.17N.TA=2TB=0.83N.\frac{15}{2}·2·(15/100)-\frac{85}{2}·2·(85/100)+60·T_B=0,\\\space\\ T_B=1.17\text N.\\ T_A=2-T_B=0.83\text N.


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