Question #231852
How much tension must a rope withstand if it used to accelerate 1200 kg
car vertically upward at 0.80 m/s2?
1
Expert's answer
2021-09-01T11:20:04-0400

The tension in a rope

F=m(a+g)=1200kg(0.80+9.8)m/s2=12720NF=m(a+g)\\ =1200\:\rm kg*(0.80+9.8)\:\rm m/s^2=12720\:\rm N


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