Question #231638

Four sled dogs are pulling a 1000 kg load. Sled dog A is pulling the load at 20 N, 10° north of east. Sled dog B is pulling the load at 55 N, 70° north of east. Sled dog C is pulling the load at 45 N, 33° north of west, while sled dog D exerts 30 N at a direction of 80° south of west. What is the resultant force acting on the load?

Scale: 1 cm = 10 N




Expert's answer

Fx=20cos⁡10+55cos⁡70−45cos⁡35−33cos⁡35=−4.44 NFy=20sin⁡10+55sin⁡70+45sin⁡33−30sin⁡80=50.1 NF=4.442+50.12=50.3 Nθ=arctan⁡4.4450.1=5° W of NF_x=20\cos{10}+55\cos{70}\\-45\cos{35}-33\cos{35}=-4.44\ N\\ F_y=20\sin{10}+55\sin{70}\\+45\sin{33}-30\sin{80}=50.1\ N\\\\F=\sqrt{4.44^2+50.1^2}=50.3\ N\\ \theta=\arctan{\frac{4.44}{50.1}}=5\degree \text{ W of N}


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