Answer to Question #231089 in Physics for Jonathon

Question #231089

An ant of mass 2.0 × 1 0 −6  kg is attempting to cross a tightrope in order to reach some food. Whilst crossing the tightrope, a gust of wind causes a force,  F w  , to act vertically upwards on the ant with a force of 2.5 × 1 0 −5  N. Take the acceleration due to gravity to be 9.8 m s−2.

What is the magnitude and direction of the force due to gravity acting on the ant?


1
Expert's answer
2021-08-31T08:59:08-0400
Fg=mgFg=(2106)(9.8)=2.0105 NF_g=mg\\F_g=(2\cdot10^{-6})(9.8)=2.0\cdot10^{-5}\ N

The  direction of the force due to gravity acting on the ant is downwards.


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