The total forward force on the car is 400 N when the car is travelling at a constant speed of 10 ms-1 along a level road. What is the total backward force on the car?
Fforward−Fbackward=ma=0→Fbackward=Fforward=F_{forward}-F_{backward}=ma=0 \to F_{backward}=F_{forward}=Fforward−Fbackward=ma=0→Fbackward=Fforward=
=400 (N)=400 \ (N)=400 (N)
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