Question #229976

Determine the specific gravity of a fluid having viscosity of 0.0a poise and kinematic viscosity of 0.0da stokes


Expert's answer

The density of a liquid can be expressed in terms of kinematic viscosity and viscosity:


ρL=μLνL.\rho_L=\frac{\mu_L}{\nu_L}.

Specific gravity is the ratio of density of a liquid to the density of water:


s=ρLρW.s=\frac{\rho_L}{\rho_W}.

So:


s=μLρWνL=0.01⋅101000⋅0.01⋅10=0.001.s=\frac{\mu_L}{\rho_W\nu_L}=\frac{0.01·10}{1000·0.01·10}=0.001.


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