Question #229837

Determine the power involved if a 50kg student run 100 m in 11 second.


1
Expert's answer
2021-08-26T08:10:22-0400

Given:

m=50kgm=50\:\rm kg

d=100md=100\:\rm m

t=11st=11\:\rm s


The speed of the student

v=dt=100m11s=9.1m/sv=\frac{d}{t}=\frac{100\:\rm m}{11\:\rm s}=9.1\:\rm m/s

The power

P=Et=mv2/2t=50kg(9.1m/s)2/211s=188WP=\frac{E}{t}=\frac{mv^2/2}{t}\\=\frac{50\:\rm kg*(9.1\:\rm m/s)^2/2}{11\:\rm s}=188\:\rm W


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