Question #229737
What is the magnitude and direction of a Force with components Fx = -37kN and Fy = - 44kN?
1
Expert's answer
2021-08-26T08:10:51-0400
F=372+442=57.5 kNθ=180+arctan4437=230°F=\sqrt{37^2+44^2}=57.5\ kN\\ \theta=180+\arctan{\frac{44}{37}}=230\degree


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