Question #229736
What are the values of the components of the 53kN Force directed up to the left at an angle of 25 degrees with respect to x-axis?
1
Expert's answer
2021-08-25T17:23:24-0400

Given:

F=53kNF=53\:\rm kN

θ=25\theta=25^{\circ}


The components of the force

Fx=Fcosθ=53kNcos25=48kNF_x=F\cos\theta=53\:\rm kN*\cos 25^{\circ}=48\: kN

Fy=Fsinθ=53kNsin25=22kNF_y=F\sin\theta=53\:\rm kN*\sin 25^{\circ}=22\: kN


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