Question #229040
An engine raises 100 kg of water through a height of 60m in 20 seconds. What is the power of the engine(take g as 10ms-2)
1
Expert's answer
2021-08-24T14:42:30-0400

In order to raise m=100kgm = 100kg of water through the height h=60mh = 60m the following amount of work is required:


W=mghW = mgh

By definition, the power is:


P=Wt=mghtP = \dfrac{W}{t} = \dfrac{mgh}{t}

where t=20st= 20s is the time reqired to do the work.

Thus, obtain:


P=100kg10m/s260m20s=3000WP = \dfrac{100kg\cdot 10m/s^2\cdot 60m}{20s} = 3000W

Answer. 3000 W.


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