Question

An electron moves in a circular path perpendicular to a uniform magnetic field of intensity of 4.7×10^-4T. if the electron moves with a speed of 106m/s, Calculate the radius of the circular path

Answer 1

$$r=\frac{mv}{eB}\\r=\frac{(9.11\cdot10^{-31})(1\cdot10^{6})}{(1.6\cdot10^{-19})(4.7\cdot10^{-4})}=0.012\ m$$