Question #228256

The resistance of a 2 km length of cable of cross-sectional area 2 mm² and resistivity of

2x10-8 Ωm is


1
Expert's answer
2021-08-23T12:40:27-0400



R=ρ⋅lA=2⋅10−8⋅20002⋅10−6=20 (Ω)R=\rho\cdot\frac{l}{A}=2\cdot10^{-8}\cdot\frac{2000}{2\cdot10^{-6}}=20\ (\Omega) . Answer




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