A coil of wire has a resistance of 10 Ω at 0°C. If the temperature coefficient of resistance for the wire is 0.004/°C, its resistance at 100°C is
Rt=R0(1+αt)=10⋅(1+0.004⋅100)=14 (Ω)R_t=R_0(1+\alpha t)=10\cdot(1+0.004\cdot100)=14\ (\Omega)Rt=R0(1+αt)=10⋅(1+0.004⋅100)=14 (Ω) . Answer
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