Question

A sling shot accelerates a 12g stone to a velocity of 35m/s within a distance of 5cm. To what (constsnt) force is the stone subjected during the acceleration.

Answer 1

The acceleration of a stone

$$a=\frac{v^2}{2d}=\frac{(35\:\rm m/s)^2}{2*0.05\:\rm m}=12250\:\rm m/s^2$$

The force

$$F=ma=0.012\:\rm kg*12250\:\rm m/s^2=147\: N$$