Question #228168

A 5kg mass slides without friction down a 30° inclined plane l.after sliding 2m,it hits and stick to a pan attached to a light spring whose force constant is 4300Nm.

By how much is the spring compressed.

Calculate the period of the resulting simple harmonic motion of the mass


1
Expert's answer
2021-08-23T12:41:41-0400

The 2m-long incline at 30° is equivalent to the following height:


h=Lsin30°=1 m.h=L\sin30°=1\text{ m}.

The potential energy is, therefore:


PE=mgh=49 J.PE=mgh=49\text { J}.

According to energy conservation, this is the kinetic energy:


KE=49 J.KE=49\text{ J}.

According to energy conservation, this is the elastic potential energy:


49=12kx2, x=249k=0.15 m.49=\frac12kx^2,\\\space\\ x=\sqrt{\frac{2·49}{k}}=0.15\text{ m}.

The period of oscillations:


T=2πmk=0.0214 s.T=2\pi\sqrt{\frac mk}=0.0214\text{ s}.


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