Question #227815
2 coin lie 2.3m apart in vacuum. they carry identical charges. how long is the charge on each if a coin experience a force of 4.5N.(q=51.4C)
1
Expert's answer
2021-08-20T12:55:46-0400
F=kq2r24.5=(9109)q22.32q=51.4 μCF=k\frac{q^2}{r^2}\\4.5=(9\cdot10^9)\frac{q^2}{2.3^2}\\q=51.4\ \mu C


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