Answer to Question #227215 in Physics for mohd sohil

Question #227215

a stone is dropped into a well it travels in air for 5 seconds and touches the water available in well approximate and find the depth of well

Expert's answer

The depth of well

"d=\\frac{gt^2}{2}=\\frac{9.8\\:\\rm m\/s^2*(5\\: s)^2}{2}=122.5\\:\\rm m"

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