Answer to Question #227215 in Physics for mohd sohil

Question

a stone is dropped into a well it travels in air for 5 seconds and touches the water available in well approximate and find the depth of well

Answer 1

The depth of well

$$d=\frac{gt^2}{2}=\frac{9.8\:\rm m/s^2*(5\: s)^2}{2}=122.5\:\rm m$$