Question

A mass vibrates through amplitude of 2.0cm in simple harmonic motion with period 1.0s. what distance is moved from the distance of oscillation in 0.4s

Answer 1

A - amplitude (cm)

T - period (s)

t - time variable (s)

x(t) - displacement (cm)

Comply the equation:

$$x(t)=A\sin\bigg(\frac{2\pi}{T}t\bigg),\\\space\\ x(0.4)=2\sin\bigg(\frac{2\pi}{1}·0.4\bigg)=0.088\text{ cm}.$$