Question #225755

a car traveling with initial velocity of 22.4 m/s skids to a stop in 22.5 displacement. What is the skidding displacement of the car


Expert's answer

Given:

vi=22.4m/s,vf=0.v_i=22.4\:{\rm m/s},\quad v_f=0.

d=22.5md=22.5\:\rm m

The displacement

d=vf2vi22ad=\frac{v_f^2-v_i^2}{2a}

Hence, the acceleration

a=vf2vi22d=0222.42222.5=11.2m/s2a=\frac{v_f^2-v_i^2}{2d}=\frac{0^2-22.4^2}{2*22.5}=-11.2\:\rm m/s^2


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