Question

 A water tank has a hole 3.0 cm^2 in area located 2.0 m below the water surface. How many kilograms of water emerge from the hole per second?

Answer 1

$$\frac{dm}{dt}=\rho Av\\\frac{dm}{dt}=(3\cdot10^{-4})(1000)\sqrt{2(9.8)(2)}=1.9\frac{kg}{s}$$