Question

Angular displacement is 2t^2-9t +4 radius find the angular velocity and angular acceleration

Answer 1

By defintion, the angular velocity and angular acceleration are the first and second derivative of angular displacement $\varphi(t) = 2t^2 - 9t + 4$ with respect to time.

Thus, obtain velocity:

$$\omega (t) = (2t^2 - 9t + 4)' = 4t - 9$$

and acceleration:

$$\varepsilon(t) = (2t^2 - 9t + 4)'' = (4t - 9)' = 4$$