Question #224611
  1. The force on a particle of mass 3.0 kg varies with position according to F(x) = -2.0x² (x in meters, F(x) in newtons). The particle's velocity at x = 2.0 m is 8.0 m/s. Calculate the mechanical energy of the particle using (a) the origin as the reference point and (b) x = 5.0 m as the reference point. (c) Find the particle's velocity at x = 1.0 m. Do this part of the problem for each reference point.
  2. (a) How high a hill can a car coast up (engines disengaged) if work done by friction is negligible and its initial speed is 210 km/h? (b) If, in actuality, a 750-kg car with an initial speed of 210 km/h is observed to coast up a hill to a height 25.0 m above its starting point, how much thermal energy was generated by friction? (c) What is the average force of friction if the hill has a slope of 2.5° above the horizontal?

 


1
Expert's answer
2021-08-09T16:24:32-0400

Given:

m=3.0kgm=3.0\:\rm kg

F(x)=2.0x2F(x)=-2.0x^2

v=8.0m/sv=8.0\:\rm m/s

The mecanical energy

E(x)=mv22+V(x)E(x)=\frac{mv^2}{2}+V(x)V(x)=dFdx=4.0xV(x)=-\frac{dF}{dx}=4.0x

(a)

E(0)=E(2)=3.08.022+4.02.0=104JE(0)=E(2)=\frac{3.0*8.0^2}{2}+4.0*2.0=104\:\rm J

(b)

E(5)=E(0)=E(2)=104JE(5)=E(0)=E(2)=104\:\rm J

(c)

E(1)=mv22+V(1)=104E(1)=\frac{mv^2}{2}+V(1)=104

3.0v22+4.01.0=104J\frac{3.0*v^2}{2}+4.0*1.0=104\:\rm J

v=8.2m/sv=8.2\:\rm m/s


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