Given:
"m=3.0\\:\\rm kg"
"F(x)=-2.0x^2"
"v=8.0\\:\\rm m\/s"
The mecanical energy
"E(x)=\\frac{mv^2}{2}+V(x)""V(x)=-\\frac{dF}{dx}=4.0x"(a)
"E(0)=E(2)=\\frac{3.0*8.0^2}{2}+4.0*2.0=104\\:\\rm J"(b)
"E(5)=E(0)=E(2)=104\\:\\rm J"(c)
"E(1)=\\frac{mv^2}{2}+V(1)=104""\\frac{3.0*v^2}{2}+4.0*1.0=104\\:\\rm J"
"v=8.2\\:\\rm m\/s"
Comments
Leave a comment