Question #223615
A spring has a force constant k=1200n/m. How far must the spring be stretched for 80j of potential energy to be stored in it?
1
Expert's answer
2021-08-05T14:17:47-0400
E=0.5kx280=0.5(1200)x2x=0.365 mE=0.5kx^2\\80=0.5(1200)x^2\\x=0.365\ m


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