Answer to Question #222529 in Physics for san

Question

The air pressure inside the pressure cooker is 1.0 x 10⁵ Pa at the temperature of 28 °C.

What is the temperature, in kelvin needed to increase the pressure to 1.3 x 10⁵ Pa?

Answer 1

The Charles's law says

$$\frac{P_1}{T_1}=\frac{P_2}{T_2}$$

Hence,

$$T_2=T_1\frac{P_2}{P_1}\\ =(28+273)\frac{1.3\times 10^5}{1.0\times 10^5}=391\:\rm K$$

$$t_2=T_2-273=391-273=118\:\rm ^{\circ}C$$