Question

what is formula of projectile motion

Answer 1

Given:

$v_0,\; \theta$

Equations of motion of a projectile are as follows

$$x(t)=v_0\cos\theta* t\\ y(t)=v_0\sin\theta* t-\frac{gt^2}{2}$$

The range

$$R=\frac{v_0^2\sin2\theta}{g}$$

The maximum height

$$H=\frac{v_0^2\sin^2\theta}{2g}$$