Question #222003

1. A rubber band is stretched from its resting position a distance of 0.15 m and follows Hooke’s Law with a spring constant of k = 2.3 N/m. What is the force being exerted on the rubber band? 

 


1
Expert's answer
2021-08-12T16:19:54-0400

The Hooke’s law says

F=kx=2.3N/m0.15m=0.35NF=kx=2.3\:\rm N/m*0.15\: m=0.35\: N

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS