Question #221967

A 1200 kg automobile travels at 9 m/s.  

  1. What is its kinetic energy? 
  2. What net work would be required to bring it to a stop? 
1
Expert's answer
2021-08-05T11:35:56-0400

Given:

m=1200kgm=1200\:\rm kg

v=9m/sv=9\:\rm m/s

1)

Ek=mv22=1200922=48600JE_k=\frac{mv^2}{2}=\frac{1200*9^2}{2}=48600\:\rm J

2)

W=ΔEk=48600JW=-\Delta E_k=-48600\:\rm J


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