Question

Jim Carrey and his pet budgie go everywhere together. One afternoon Jim Carrey decides to go for a walk. Jim Carrey walks 6.0 x 10² m [N] in 4.0 minutes, then walks 0.20 km [E] in 2.5 minutes.

Determine Jim Carrey's average velocity

Answer 1

Average velocity is total displacement over total time. The displacement:

$$D=\sqrt{600^2+200^2}=632\text{ m}.$$

The time:

$$t=4+2.5=6.5\text{ min}.$$

Average velocity:

$$v_\text{av}=\frac{632}{6.5}=97.2\text{ m/min}.$$