Answer to Question #221137 in Physics for Odaghi

Question #221137

what is the speed of an electron released at the negative plate before reaching the positive plate where distance is 0.02 m potential difference is 250 volt and electric field is 125,000 N/C

Expert's answer

"0.5mv^2=eU\\\\v^2=2(1.7588\\cdot10^{11})(250)\\\\v=9.38\\cdot10^6\\frac{m}{s}"

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