Question #220836

the intensity level of two sounds are 100dB and 50dB, ?hat is the ratio of their intensities?


1
Expert's answer
2021-07-28T03:29:04-0400

The intensity level of the sound

β=10lgII0\beta=10\lg\frac{I}{I_0}

Hence

β2β1=10lgI2I1\beta_2-\beta_1=10\lg\frac{I_2}{I_1}

I2I1=10(β2β1)/10=10(10050)/10=100000\frac{I_2}{I_1}=10^{(\beta_2-\beta_1)/10}=10^{(100-50)/10}=100000

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