Question

If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how

much power was used

Answer 1

By the definition of the power, we have:

$$P=Fv=mg\dfrac{d}{t},$$ $$P=47\ kg\cdot9.8\ \dfrac{m}{s^2}\cdot\dfrac{27\ m}{60\ s}=207\ W.$$