Question

. A particle undergoes three consecutive displacements: d1 = (15 j+ 30 j+ 12 k) cm,

d2 = (23 i - 14 i -5.0 k) cm and d3 = (-13i + 15 j) cm

Answer 1

I assume that the task is to find the total displacement.

$$\mathbf{d} = \mathbf{d}_1 + \mathbf{d}_2 +\mathbf{d}_3\\ \mathbf{d} = (15+23-13)\mathbf{i} + (30-14+15)\mathbf{j} + (12-5+0)\mathbf{k} =\\ =25\mathbf{i} +31\mathbf{j} +7\mathbf{k}$$

Answer. $\mathbf{d} = 25\mathbf{i} +31\mathbf{j} +7\mathbf{k} \space (cm)$.