Question

(a) How much heat transfer is required to raise the temperature of a 0.750-kg aluminum pot containing 2.50 kg of water from 30.0

Answer 1

$$Q=(m_ac_a+m_wc_w)(T-T_0)+mL\\ Q=((0.75)897+2.5(4200))(100-30)\\+0.75(2.256\cdot10^6)=2.47\cdot10^6J$$