Question

An object is thrown from from the ground upward with an initial speed of 3.75 m/s. How long will the object be in the air before it lands on the ground?

Answer 1

Let's first find the time that the object takes to reach its maximum height:

$$v= v_0-gt,$$ $$0= v_0-gt,$$ $$t=\dfrac{v_0}{g}=\dfrac{3.75\ \dfrac{m}{s}}{9.8\ \dfrac{m}{s^2}}=0.38\ s.$$

Finally, we can find the flight time of the object:

$$t_{flight} = 2t=2\cdot0.38\ s=0.76\ s.$$